PLEASE HELP... Big points Consider the reaction: CaCN2+ 3H20 = CaCO3 + 2NH3
How much CaCO3 is produced is 47.5 moles NH3 are produced?

The  CaCO3  produced  if  47.5   moles of  NH3  produced  is   calculated  as  follows

CaCN2  +3H2O  = CaCO3  + 2NH3

by  use   of  mole  ratio  between  CaCO3 to NH3  which  is 1:2  the  moles  of  CaCO3  is therefore =  47.5 /2= 23.75  moles

mass of CaCO3   is  therefore = moles  x  molar  mass

= 23.75 moles  x  100g/mol=  2375 grams   which  is approximate   2380  grams(answer 6)

Explanation:

there are no statements provided but here is why:

sulfur belongs to group 16 because it can be found in nature whether it is in a free or combined state.

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