Based on the following values compute delta G values for each reaction predict whether the reaction will occur spontaneously. (Hint: See Sample Problem D.) a. AH = +125 kJ, T = 293 K,
AS = 0.0350 kJ/K
b. AH = -85.2 kJ, T = 127°C,
AS = 0.125 kJ/K
C. AH = -275kJ, T = 773 K,
AS = 0.450 kJ/K

i believe the answer is a.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2