Suppose there was a release of 1 mole of Alpha emission particle and 1 mole of Beta emission particles and both particles are accelerated to 20.50 MeV. What is the total energy in kJ/nuclei? Hint: 1 MeV = 1 x 106 eV and 1 eV = 1.602 X 10-19 J and 1 kJ = 1000 J, and finally in 1 mole there are Avogadro's number of particles which is 6.02214 x 1023 particles/mole. Report your answer in scientific notation to 2 decimal places for example 1.23 x 10-4 would be entered as 1.23 E-4. 238 92 U → 4 2 He + 234 90 Th and then 234 90 Th → 0
-1e + 234 91 Pa

u i forgot the answer?

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol

if you mean hydrogen and oxygen then water is the product