An certain element Y has two naturally occurring isotopes, 6Y (isotopic mass = 6.015123 amu) and 7Y (isotopic mass = 7.016005 amu). If the atomic mass of the element is 6.9412 amu. What is the percent abundance of 6Y? Do not include the symbol "%" in your answer.

Report the correct answer to three significant figures

The percentage abundance of 6Y is 7.47%

Isotopy is the phenomenon whereby two or element have the same atomic number but different mass number due to the difference in their neutron number.

We'll begin the solving as follow:

Let A represent isotope 6Y

Let B represent isotope 7Y

From the question given above, the following data were obtained:

Mass of A = 6.015123 amu

Mass of B = 7.016005 amu

Abundance of B (B₀) = (100 – A₀%

Relative Atomic mass of Y = 6.9412 amu

The abundance of 6Y can be obtained as follow:

Collect like terms

Divide both side by –0.0100882

Therefore, the abundance of 6Y is 7.47%

Learn more:

2b2t

explanation:

2b2t