What is a saturated solution that cannot dissolve any more solute because it is too concentrated?

A saturated solution, by definition, contains an amount of solute equal to the amount of dissolved solute in equilibrium with an undissolved solute. We could, however, make a supersaturated solution in which the solvent contains more solute than would be in equilibrium with undissolved.

Explanation:   More solute cannot be dissolved at a given temperature in a saturated solution. This is because the solute dissolves in a solvent due to the space between the solvent particles, but with the continuous addition of solute, the space between the solvent particles is filled. As a result, no more solute particles can dissolve in the solvent.

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

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