In aqueous solution, when HA is reacted with Na3B, NaH2B is one of the products. H3B: pKa1 = 4.75, pka2 = 6.80, and pKa3 = 10.45

HA: pKa = 2.25

a. Write the complete molecular, complete ionic, and net ionic equations for the reaction of HA with

Na3B.

CME:

CIE:

NIE:

b. Calculate Kn for the net ionic equation.

the answer is learned

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :