The standard reduction potential for O2 in acid is 1.23 V, according to Appendix E. Calculate the reduction potential for O2 at pH 7, for all other conditions being standard. a. 0.40 V
b. 1.13 V
c. 1.23 V
d. 0.82 V
e. 1.64 V

a. +0.40 V

Explanation:

Reduction of O2 in acid medium is +1.23 V. The reduction of O2 in basic medium will be calculated by subtracting equation of acidic medium from equation in base medium.

Kw^4 = [10^-14 ] ^ 4

solving we get -0.8274

Subtracting the value from oxygen reduction in acidic medium;

+ 1.23 - 0.8274 = +0.4026

the answer would be c

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.