Ammonia, NH3(AH = 46.2 kJ), reacts with oxygen to produce water (AH = -241.8 kJ) and nitric oxide, NO (AH = 91.3 kJ), in the following reaction:
4NH3 (9) +502(g) → 6H2O(g) + 4NO(g)
What is the enthalpy change for this reaction?
Use AH men=(AHE products) - (AHe reactants).

the cold front replaces the warmer air at the ground level changing the wind to be breezy and denser.there is also an immediate drop in the temperature.

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole

the answer is a for sure mark brainliest i had got this right on usatestprep