Boyle's Law: P1V1=P2V2 The volume of a gas at 99.0 kPa is 300mL. If the pressure increases to 188kPa, what is the final volume?

158 mL

Explanation:

From the question given above, the following data were obtained:

Initial pressure (P₁) = 99.0 KPa

Initial volume (V₁) = 300 mL

Final pressure (P₂) = 188 KPa

Final volume (V₂) =?

The final volume of the gas can be obtained by using the Boyle's law equation as illustrated below:

P₁V₁ = P₂V₂

99 × 300 = 188 × V₂

29700 = 188 × V₂

Divide both side by 188

V₂ = 29700 / 188

V₂ = 158 mL

Therefore, the final volume of the gas is 158 mL.

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.