How many moles of KOH are there in 27.5 mL of 0.250 M KOH? Question 2 options:

4.31 × 10−3 mol KOH

6.88 × 10−3 mol KOH

7.24 × 10−3 mol KOH

8.13 × 10−3 mol KOH

9.21 × 10−3 mol KOH

6.88 × 10^-3mol

Explanation:

Molarity = number of moles (n) ÷ volume (V)

According to this question, there in 27.5 mL of 0.250 M KOH, the number of moles of KOH can, therefore, be calculated as follows:

number of moles = molarity × volume

Volume of KOH = 27.5mL = 27.5/1000

= 0.0275L

n = 0.0275 × 0.250

n = 0.006875 mol

n = 6.88 × 10^-3mol

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.

the answer is c

tell me if wrong