Hỗn hợp M gồm 0.25mol ancol no đơn chức x và 0,25mol axit cacboxylic y cùng là mạch hở nếu đốt cháy hoàn toàn lượng M trên thì thu được 22,4 lít khí co2 và 18gam h2o

- lead + phosphoric acid = hydrogen + lead(ii) phosphate

the answer is   c.) 1575 j.

explanation:

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol