How many moles of Cd and of N are contained in 132.4 g of Cd(N03)2-4H20? (b) How many molecules of water of hydration are in this same amount?

The given amount of contains 0.430 moles of Cd, 0.860 moles of N and molecules of water.

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

......(1)

Given mass of = 132.4 g

Molar mass of = 308.5 g/mol

Plugging values in equation 1:

1 mole of contains 1 mole of Cd, 2 moles of nitrogen atom (N), 10 moles of oxygen atom (O) and 8 moles of hydrogen atom (H).

So, 0.430 moles of will contain = of Cd and of N

According to the mole concept:

1 mole of a compound contains number of molecules

So, 0.430 moles of will contain = number of water molecules.

Hence, the given amount of contains 0.430 moles of Cd, 0.860 moles of N and molecules of water.

you need to have a picture of the atom that way we can answer it

c. 4.54 x 10–12 j happens to be correct