In aqueous solution, when HA is reacted with Na3B, NaH2B is one of the products. H3B: pKa1 = 4.75, pka2 = 6.80, and pKa3 = 10.45
HA: pKa = 2.25
a. Write the complete molecular, complete ionic, and net ionic equations for the reaction of HA with
Na3B.
CME:
CIE:
NIE:
b. Calculate Kn for the net ionic equation.

explanation:

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