An electrolytic cell transferred 0.10 m o l of electrons when a constant current of 2.0 A was applied. How many hours did this take?

1.34 hr

Explanation:

From the question given above, the following data were obtained:

Number of mole of electron (e) = 0.1 mole

Current (I) = 2 A

Time (t) =?

Next, we shall determine the quantity of electricity transferred. This can be obtained as follow:

1 mole of electron = 96500 C

Therefore,

0.1 mole of electron = 0.1 × 96500

0.1 mole of electron = 9650 C

Thus, 9650 C of electricity was transferred.

Next, we shall determine the time. This can be obtained as follow:

Current (I) = 2 A

Quantity of electricity (Q) = 9650 C

Time (t) =?

Q = It

9650 = 2 × t

Divide both side by 2

t = 9650 / 2

t = 4825 s

Finally, we shall convert 4825 s to hour. This can be obtained as follow:

3600 s = 1 hr

Therefore,

4825 s = 4825 s× 1 hr / 3600 s

4825 s = 1.34 hr

Thus, the time taken is 1.34 hr

water is used to store them because it would keep the radiation from getting out in the open and causing harm to the workers

i'm assuming that the correct answer is indeed the first one/ "a"..