2HGO(s) + 43.4 kcal -> 2Hg(I) + O2(g)

x = -9, 0 = -1, x \ne 0

Explanation:

[-54/x = 6  0x = 9]

Isolate x for - 54/x = 6 : x = -9

-54/x = 6

Multiply both sides by x

-54/x = 6x

Simplify - 54/x x :  -54

-54x x = 6x

Multiply fractions: a . b/c = a . b/c

= -54x/x

Cancel the common factor: x

= -54

- 54 = 6x

Switch sides

6x = -54

Divide both sides by 6

6x/6 = -54/6

Simplify

6x/6 = -54/6

Simplify 6x/6:  -9

6x/6

Divide the numbers: 6/6 = 1

= x

Simplify

-54/6

Apply the fraction rule: -a/b = -a/b

= -54/6

Divide the numbers: 54/6 = 9

= -9

x = -9

Verify solutions

Find underfined (singularity) point: x = 0

Take the denominator (s) of - 54/x and compare to zero

x = 0

Combine undefined points with solutions:

x = -9

Substitute x = -9

[ o(-9) = 9]

Simplify

0(-9) = 9

Simplify

0(-9): -90

Remove parentheses: (-a) = -a

= -0 . 9

-90 = 9

[-90 = 9]

Isolate o for -90 = 9 : o = -1

-90 = 9

Divide both sides by -9

-90/-9 = 9/-9

Simplify

0 = -1

The solutions to the system of equations are:

x = -9, 0 = -1, x \ne 0

answer: e.   sour taste

explanation: acids are those substances which dissociates in water to give ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. acids are sour in taste. example: hcl

bases are those substances which dissociates in water to give ions or accepts ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. bases are bitter in taste. bases are slippery in nature.