Chemistry, 13.07.2021 15:30 ginocousins06
A 0.879 g sample of a CaCl2 ∙ 2 H2O / K2C2O4 ∙ H2O solid salt mixture is dissolved in 150 mL of deionized water. A precipitate forms which is then filtered and dried. The mass of this precipitate is 0.284 g. The limiting reagent in the salt mixture was later determined to be CaCl2 ∙ 2 H2O.
a. Write the molecular form of the equation for the reaction.
b. Write the net ionic equation for the reaction
c. How many moles of CaCl2 ∙ 2 H2O reacted in the reaction mixture?
d. How many grams of CaCl2 ∙ 2 H2O reacted in the reaction mixture?
e. How many moles of K2C2O4 ∙ H2O reacted in the reaction mixture?
f. How many grams of K2C2O4 ∙ H2O reacted in the reaction mixture?
g. How many grams of K2C2O4 ∙ H2O in the salt mixture remain unreacted?
h. What is the percent by mass of each salt in the mixture?
Answers: 3
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A 0.879 g sample of a CaCl2 ∙ 2 H2O / K2C2O4 ∙ H2O solid salt mixture is dissolved in 150 mL of deio...
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