11. What is the balanced equation for this reaction, which takes place in a basic solution? Cr(OH)3( s) + ClO3 –( aq) → CrO4 2( aq) + Cl –( aq) Cr(OH)3( s) + 2ClO3 –( aq) + 4OH –( aq) → 2CrO4 2 –( aq) + Cl –( aq) + 3H2O( l) 2Cr(OH)3( s) + ClO3 –( aq) + 4OH –( aq) → 2CrO4 2 –( aq) + Cl –( aq) + 5H2O( l) Cr(OH)3( s) + 2ClO3 –( aq) + 6OH –( aq) → 3CrO4 2 –( aq) + 2Cl –( aq) + 2H2O( l) 2Cr(OH)3( s) + 2ClO3 –( aq) + 6OH –( aq) → 2CrO4 2 –( aq) + 2Cl –( aq) + 7H2O( l)

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

it is the most commonly accepted one

answer seismograph;