Chemistry, 07.07.2021 03:40 meadowsoares7
Utilizar a Lei de Hess. Obs.: dH (delta H)
A partir das reações abaixo, calcule calor de hidratação (dissolução) do hidróxido de potássio KOH.
K(s) + H2O(l) -- > KOH(aq) + 0,5 H2(g) dH= -48 kcal
H2(g) + 0,5 O2(g) -- > H2O(l) dH = - 69 kcal
K(s) + 0,5 O2(g) + 0,5 H2(g) -- > KOH(s) dH = -103 kcal
Dissolução do KOH, passa do sólido para aquoso
KOH(s) -- > KOH(aq)
Answers: 3
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Utilizar a Lei de Hess. Obs.: dH (delta H)
A partir das reações abaixo, calcule calor de hidratação...
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