How to work out the amount of carbon dioxide that is released when fully combusted with 4kg of ethanol?

There is 7642 grams of CO2 released

Explanation:

Step 1: Data given

carbon dioxide = CO2

Molar mass of carbon dioxide = 44.01 g/mol

Mass of ethanol = 4 kg = 4000 grams

Molar mass of ethanol = 46.07 g/mol

Step 2: The reaction

Combustion of ethanol means there is oxygen (O2) added. The products are CO2 and H2O.

C2H5OH + 3O2 → 2CO2 + 3H2O

Step 3: Calculate number of moles of ethanol

Moles ethanol = mass ethanol / molar mass ethanol

Moles ethanol = 4000 grams / 46.07 g/mol

Moles ethanol = 86.82 moles

Step 4: Calculate number of moles CO2

For 1 mol ethanol we need 3 moles to produce 2 moles CO2 and 3 moles H2O

For 86.82 moles of ethanol we'll have 2*86.82 = 173.64 moles CO2

Step 5: Calculate mass of CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 173.64 moles * 44.01 g/mol

Mass CO2 = 7642 grams

There is 7642 grams of CO2 released

the answer is 0.8m.

by: nicholas