For the unbalanced reaction below, calculate how many grams of oxygen form when 2.72 g of potassium chlorate completely reacts. KClO3(s) --> KCl(s) + O2(g)

1.06g O2

Explanation:

Let's first balance the equation.

2KClO3 > 2KCl + 3O2

We're going to go from:

Grams of KClO3: 2.72gto moles, using molar mass of KClO3: 122.5g/molWe'll convert to O2 using a mole ratio, where we have 2 mols of KClO3 to 3 mols of O2.To grams of O2 using molar mass: 32g/mol

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