How many moles of NaOH are present in 22.0 mL of 0.140 M NaOH?

Mole of NaOH = 0.00308 mole

Explanation:

From the question given above, the following data were obtained:

Volume = 22 mL

Molarity = 0.140 M

Mole of NaOH =?

Next, we shall convert 22 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

22 mL = 22 mL × 1 L / 1000 mL

22 mL = 0.022 L

Finally, we shall determine the number of mole of NaOH in the solution. This can be obtained as shown below:

Volume = 0.022 L

Molarity = 0.140 M

Mole of NaOH =?

Molarity = mole / Volume

0.140 = Mole of NaOH / 0.022

Cross multiply

Mole of NaOH = 0.140 × 0.022

Mole of NaOH = 0.00308 mole

Thus, 0.00308 mole of NaOH is present in the solution.

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