calculate the volume of a 3.0 mol of oxygen, b 50.0g of hydrogen cloride gas at STP(molar volume of gas is 22.4dm³,molar mass of Hcl=36.5g)​

98L is the volume of the gas

Explanation:

To solve this question we need to find  the moles of O2 + moles HCl. With these moles and PV = nRT we can find the volume as follows:

Moles O2: 3.0mol

Moles HCl:

50.0g * (1mol/36.5g) = 1.37 moles HCl

Total moles:

3.0mol O2 + 1.37 mol HCl = 4.37 moles

PV = nRT

V = nRT/P

Where V is volume in L, n are moles = 4.37mol, R is gas constant = 0.082atmL/molK, T is absolute temperature = 273.15K at STP, P = 1atm at STP

V = 4.37mol*0.082atmL/molK*273.15K / 1atm

V = 98L is the volume of the gas

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