What is the enthalpy change of (2 g) of water from ice at -10 °C to vapor at 110°C and 101.3 kPa? AH, = 80 cal/g at 0°C and (101.3 kPa)
AH, = 540 cal/g at 100°C and (101.3 kPa) The heat capacity equations:
Liquid [J/(g mol) (K)] = 18.3+4710^-2 ×T
Vapor [J/(g mol) (C)]= 33.5 + 0.69×10^-2 × T

Ice [cal/(g C)] = 0.5​

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.

cytokinesis is the splitting of a cell membrane to form 2 identical daughter cells. it's similar to mitosis as both cells have identical copies of dna and cytokinesis is a step in the mitotic cycle.