Calculate the mass of CaCL2 formed when 5 moles of chlorine reacts with calcium metal

555 g of CaCl₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

Ca + Cl₂ —> CaCl₂

From the balanced equation above,

1 mole of Cl₂ reacted to produce 1 mole of CaCl₂.

Next, we shall determine the number of mole of CaCl₂ produced by the reaction of 5 moles of Cl₂. This can be obtained as follow:

From the balanced equation above,

1 mole of Cl₂ reacted to produce 1 mole CaCl₂.

Therefore, 5 moles of Cl₂ will also react to produce 5 moles of CaCl₂.

Thus, 5 moles of CaCl₂ were obtained from the reaction.

Finally, we shall determine the mass of 5 moles of CaCl₂. This can be obtained as follow:

Mole of CaCl₂ = 5 moles

Molar mass of CaCl₂ = 40 + (35.5×2)

= 40 + 71

= 111 g/mol

Mass of CaCl₂ =?

Mass = mole × molar mass

Mass of CaCl₂ = 5 × 111

Mass of CaCl₂ = 555 g

Therefore, 555 g of CaCl₂ were obtained from the reaction.

hey there!

boiling point is the temperature at which the vapor pressure of the liquid equals atmospheric pressure. the vapor pressure of solvent molecules is decreased when a solute is added, so a higher temperature is required to increase the number of solvent molecules in the gas phase above the liquid.

at the freezing point, the vapor pressures of the solid and liquid are equal; a lower temperature is needed to reduce the number of solvent particles above the liquid.

hope this you

tobey