Câu 7. Cho 4,6 gam một axit cacboxylic no, đơn chức mạch hở tác dụng với 100 ml dd chứa KOH 1M, NaOH 1M. Sau khi phản ứng hoàn toàn thu được 12,4 gam chất rắn khan. CTPT của X là

there are two significant figures.

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol