If this experiment was performed again, but this time, 5.0 g of the mixture were used, then, assuming the same mass percentages (5 % cellulose, 47.5 % caffeine, and 47.5 % benzoic acid), what is the theoretical mass (in g) of cellulose in this mixture

the theoretical mass of cellulose in this mixture is 0.25 grams

Explanation:

Given the data in the question;

mass of the mixture = 5.0 gram

mass percentage of cellulose = 5%

mass percentage of caffeine = 47.5%

mass percentage of benzoic acid = 47.5%

so mass of caffeine  in the mixture will be;

⇒ ( mass percentage of cellulose ) × ( mass of the mixture )

=  5% × 5.0 gram

= ( 5 / 100 ) × 5.0 grams

= 0.05 × 5.0 grams

= 0.25 grams

Therefore, the theoretical mass of cellulose in this mixture is 0.25 grams