Fe2O3 (s) + CO (g) -> Fe(s) + CO2 (g) (unbalanced) 1.Calculate the number of grams of CO that can react with 0.150kg of Fe2O3
2. Calculate the number of grams of Fe and the number of grams of CO2 formed
when 0.150 kg of Fe2O3 reacts

1. 78.9g of CO

2. 104.9g Fe and 124.0g CO2

Explanation:

Based on the balanced reaction:

Fe2O3 (s) + 3CO (g) -> 2Fe(s) + 3CO2 (g)

1 mole of Fe2O3 reacts with 3 moles of CO to produce 2 moles of Fe and 3 of CO2

1. The moles of 0.150kg = 150g of Fe2O3 -Molar mass: are:

150g * (1mol / 159.69g) = 0.9393 moles Fe2O3

Moles CO:

0.9393 moles Fe2O3 * (3mol CO / 1mol Fe2O3) = 2.818 moles CO

Mass CO -Molar mass: 28.01g/mol-:

2.818 moles CO * (28.01g/mol) = 78.9g of CO

2. The moles of Fe produced are:

0.9393 moles Fe2O3 * (2mol Fe / 1mol Fe2O3) = 1.8786 moles Fe

Mass Fe -Molar mass: 55.845g/mol-:

1.8786 moles Fe * (55.845g/mol) = 104.9g Fe

The moles of CO2 produced are:

0.9393 moles Fe2O3 * (3mol CO2 / 1mol Fe2O3) = 2.818moles CO2

Mass CO2 -Molar mass: 44.01g/mol-:

2.818moles CO2 * (44.01g/mol) = 124.0g CO2

i do not get it   at all

the answer is 75.0%.