Consider the reaction of Copper with Sulfur: Cu +S → Cus. Using the below data, which of following is true?

A. Sulfur was the limiting reactant; 1.61 g of sulfur were reacted.
B. Copper was the limiting reactant; 1.32 g of sulfur were unreacted
C. Copper (II) sulfide was the limiting reactant; 4.78 g was formed.
D. There was no limiting reactant; both reactants remained in excess.

B. Copper was the limiting reactant; 1.32 g of sulfur were unreacted

Explanation:

Cu + S → CuS

With the two points above in mind, the only option left is B.

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.