g A student in a laboratory at SDSU has purified 81.0 mg of skeletal muscle glycogen. After exhaustive methylation (to methylate all free hydroxyl groups) and complete hydrolysis (to monosaccharide units), she detects 62.5 micromoles of 2,3-dimethylglucose, 62.5 micromoles of 2,3,4,6-tetramethylglucose, 373.5 micromoles 2,3,6-trimethylglucose, and 1.5 micromoles of 1,2,3,6-tetramethylglucose. What fraction of the monosaccharide units in this sample of glycogen are branch points

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied