A solution has a [H3O+] of 1 × 10−3 M. What is the [OH−] of the solution? A. 11 M
B. 14 M
C. 1 × 10−14 M
D. 1 × 10−11 M

D. 1x10⁻¹¹ M

Explanation:

For any given aqueous solution the following formula is true:

1x10⁻¹⁴ = [H₃O⁺] * [OH⁻]

1x10⁻¹⁴ is the ion-product constant of water, Kw.

We input the given value of [H₃O⁺]:

1x10⁻¹⁴ = 1x10⁻³ * [OH⁻]

And solve for [OH⁻]:

[OH⁻] = 1x10⁻¹¹ M

Thus the correct answer is option D. 1x10⁻¹¹ M.

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o