What mass of lead (II) chloride would be produced when a solution containing 23.4g of sodium chloride is mixed with a solution containing excess lead (II) nitrate? The equation for this reaction is: Pb(NO3) 2(aq) +2NaCl(aq)-->PbCl2(s) +2NaNO3(aq).

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles

i believe it is a.) released into

explanation:

i just learnt this recently but i need to look through my notes again

its first and third is your answer i did the qustion the fourth isnt right