In the chemical reaction between aqueous magnesium chloride and sodium metal, what chemical amount (mol) of magnesium metal can be precipitated (produced) with 12.6 mol of sodium metal?

6.3moles

Explanation:

The balanced equation of the reaction described above between aqueous magnesium chloride and sodium metal is as follows:

MgCl2(aq) + 2Na(s) → 2NaCl(aq) + Mg(s)

From the above equation, 2 moles of sodium metal (Na) produces 1 mole of Magnesium metal (Mg)

Hence, 12.6 mol of Na will produce (12.6/2) mol of Mg.

12.6/2 = 6.3moles of Mg metal.