A sample of 41.9 g of aluminum is reacted with 67.2 g of chlorine gas to produce aluminum trichloride. Using the balanced equation below, predict which is the limiting reactant and the maximum amount in moles of aluminum trichloride that can be produced. 2A1+ 3Cl2 → 2AlCl3 A, aluminum, 1.55 moles B. chlorine gas, 0.632 moles C. aluminum, 0.865 moles D. chlorine gas, 0.954 moles​