Chegg Write the balanced half-reactions for the following oxidation-reduction reaction that occurs in acid solution. Determine the number of electrons that appears in the balanced half reactions. Number of electrons

Reduction half-reaction: Cr₂O₇²- (aq) + 14H+ (aq) + 6e- > 2Cr³+ (aq) + 7 H₂O (l)

Oxidation half-reaction: 6 Cl- (aq) ---> 3 Cl₂ (g) + 6e-

Number of electrons = 6 electrons

Note: The question is incomplete. A similar but complete question is given below :

Write the balanced half-reactions for the following oxidation-reduction reaction that occurs in acid solution. Determine the number of electrons that appears in the balanced half reactions.

Cr₂0₇²- (aq) + CI- (aq) ---> Cr³+ (aq) + Cl₂(g)

Number of electrons =

Explanation:

A redox reaction is a reaction in which both oxidation and reduction occur simultaneously and to to the same extent.

Oxidation involves a loss of electron by atom of an element while reduction involve a gain of electrons.

A redox reaction can be split into two half-reaction; a reduction half-reaction andan oxidation half-reaction. The half-reactions in the given redox reaction is balanced as follows below:

Reduction half-reaction: Cr⁶+ being reduced to Cr³+

Cr₂O₇²- (aq) ---> Cr³+ (aq)

Since the reaction takes place in acidic medium, H+ and H₂O is added to the left and right-hand side of the equation respectively in order to balance the atoms

Cr₂O₇²- (aq) + 14H+ (aq) > 2Cr³+ (aq) + 7 H₂O (l)

Since 3 electrons are gained by Cr⁶+ in being reduced to Cr³+, 2 molecules of Cr⁶+ will accept 3 electrons each to give a total of 6 electrons

Cr₂O₇²- (aq) + 14H+ (aq) + 6e- > 2Cr³+ (aq) + 7 H₂O (l)

Oxidation half-reaction: Cl- ions are oxidized to Cl₂

Cl- (aq) ---> Cl₂

Two Cl- will each lose an electron to form Cl₂. Since the number of electrons gained in the reduction half-reaction is six, six electrons must be lost here as well. Therefore, the electrons involved and the number of moles of atoms involved are balanced as follows:

6 Cl- (aq) ---> 3 Cl₂ (g) + 6e-

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.