What is the concentration of a solution that has a volume of 2.5 L and contains 660 g of calcium phosphate? (molar mass of calcium phosphate = 310.18 g/mol)

0.85 M

Explanation:

Step 1: Given data

Step 2: Calculate the moles (n) corresponding to 660 g of calcium phosphate (solute)

We will use the following expression.

n = m/M

n = 660 g/(310.18 g/mol) = 2.13 mol

Step 3: Calculate the molar concentration (molarity) of the solution

Molarity is equal to the moles of solute divided by the liters of solution.

M = 2.13 mol/2.5 L = 0.85 M

the answers are

c and c