Calculate the percentage composition of oxygen and chlorine in naclo3​

To solve this problem, you simply find the total mass of each element in the molecule and divide by the molecular mass.

First, note the mass of the molecule and each element:

Na molar mass = 22.99 g/mol

Cl molar mass = 35.45 g/mol

O molar mass = 16.00 g/mol

NaClO3 molecular mass = 106.44g/mol

There is 1 Na atom per 1 NaClO3 molecule. Therefore,

% Na in NaClO3 = molar mass 1 Na atom / molar mass NaClO3 = (22.99g/mol) / (106.44g/mol) * 100 = 21.60% Na

There is 1 Cl atom per 1 NaClO3 molecule. Therefore,

% Cl in NaClO3 = molar mass 1 Cl atom / molar mass NaClO3 = (35.45g/mol) / (106.44g/mol) * 100 = 33.31% Cl

There are 3 O atoms per 1 NaClO3 molecule. Therefore,

% O in NaClO3 = 3 * molar mass 1 O Atom / molar mass NaClO3 = (3 * 16.00g/mol) / (106.44 g/mol) * 100 = 45.10% O

You can check your work by adding together the three percentages of each element, which should equal 100%. There may be slight discrepancy due to rounding. 21.60% + 33.31% + 45.10% = 100.01%.

2b2t

explanation:

2b2t

the answer is barium and copper bromide