If a sample of oxygen has a volume of 160 L at 91 degrees celsius what will the oxygen be when the temperature drops to 0.00 degrees celsius.

120 L

Explanation:

Step 1: Given data

Step 2: Convert the temperatures to the Kelvin scale

We will use the following expression.

K = °C + 273.15

K = 91°C + 273.15 = 364 K

K = 0.00°C + 273.15 = 273.15 K

Step 3: Calculate the final volume occupied by the oxygen

Assuming ideal behavior and constant pressure, we can calculate the final volume occupied by the oxygen using Charles' law.

V₁/T₁ = V₂/T₂

V₂ = V₁ × T₂/T₁

V₂ = 160 L × 273.15 K/364 K = 120 L

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)