Mass of Al wire before reaction = 3.96 g Mass of Al wire after reaction = 3.65 g

Mass of Al lost = 0.31 g

Moles of Al lost = 0.011 moles

Mass of Pb + filter paper = 4.26 g

Mass of filter paper = 0.92 g

Mass of Pb = 3.34 g

Moles of Pb formed = 0.016 moles

Recall that there were 100 mL of solution. 0.016 moles of Pb were removed from the solution.
What was the [Pb+2] for the saturated solution of PbCl2?

Recall that there was 100 mL of solution. 0.016 moles of Pb were removed from the solution. Also recall the original equilibrium:

PbCl2(s) Pb+2(aq) + 2(Cl-)(aq)

Since there are 2 Cl ions formed for every Pb ion, what was the [Cl-] for the saturated solution of PbCl2?
M

one state would change   like louisiana to texas. thats a change

explanation:

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

answer: you could do some invislibe ink.

explanation: i will tell you how to if u answer my question.