What mass of oxalic acid is required to prepare 250 mL of a 2.00 M solution?

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Explanation:

The molarity of a given solution is defined as the total number of moles of solute per litre of solution.

\(Molarity = \frac{n}{V}\)

Here,

M is the molality of the solution

n is the number of moles of the solute

V is the volume of solution given in terms of litres

Molecular weight of oxalic acid (H2C2O4.2H2O) = 126 g/mol.

M = n/V

0.1 M = n/0.25L

n = 0. 025 mol

Number of moles = Given mass/Molar mass

0. 025 mol = m / 126

m = 3.15 g

So, amount of oxalic acid is 3.15 g

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each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i