Calculate the number of representative particles of 0.0391 mol Neon gas. i need help ASAP !

2.35 × 10²² particles

Explanation:

To get the number of particles in a substance, we multiply the number of moles (n) of that substance by Avogadro's number (nA).

That is, we say;

number of atoms = n × 6.02 × 10²³

In this question, Neon gas is said to have 0.0391 moles. The number of atoms in that field.

number of particles = 0.0391 × 6.02 × 10²³

number of particles = 0.235 × 10²³

number of particles = 2.35 × 10²² particles

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."

a is the answer to this question

explanation: