Please help me :( How many atoms are present in 179.0 g of iridium?

A. 6.464x10
B. 1.157x10
C. 5696x10
D. 1078 x 10

There are atoms present in 179.0 g of iridium.

Explanation:

Given: Mass = 179.0 g

Moles is the mass of a substance divided by its molar mass. So, moles of iridium (molar mass = 192.217 g/mol) is as follows.

According to the mole concept, 1 mole of every substance contains atoms.

Therefore, atoms present in 0.931 moles are calculated as follows.

Thus, we can conclude that there are atoms present in 179.0 g of iridium.

answer; protein;

i need mutiple choices