A gas at constant volume has a pressure of 2.80 atm at 400. K. What will be the pressure of the gas at 360. K? (4 points) 2.52 atm
2.94 atm
3.11 atm
3.78 atm

It's 2.52

Explanation:

This requires Gay-Lussac's Law, in which the relationship is P1 / T1 = P2 / T2. "P" stands for Pressure and "T" is Temperature. The first pressure is 2.80, the first temperature is 400 Kelvin, the second pressure is unknown (that's what your solving for), and your second temperature is 360 Kelvin. Because you don't have the second pressure, your equation will look like 2.80 atm x 360 K / 400. This will tell you that the pressure of the gas at 360 K will be 2.52.

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and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be

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