Mass of Al wire before reaction = 3.96 g
Mass of Al wire after reaction = 3.65 g
Mass of Al l...
Mass of Al wire before reaction = 3.96 g
Mass of Al wire after reaction = 3.65 g
Mass of Al lost = 0.31 g
Moles of Al lost = 0.011 moles
Mass of Pb + filter paper = 4.26 g
Mass of filter paper = 0.92 g
Mass of Pb = 3.34 g
Moles of Pb formed = 0.016 moles
Recall that there were 100 mL of solution. 0.016 moles of Pb were removed from the solution.
What was the [Pb+2] for the saturated solution of PbCl2?
Options: 0.16, 0.016, or 0.0016
Recall that there was 100 mL of solution. 0.016 moles of Pb were removed from the solution.
Also recall the original equilibrium: PbCl2(s) Pb+2(aq) + 2(Cl-)(aq)
Since there are 2 Cl ions formed for every Pb ion, what was the [Cl-] for the saturated solution of PbCl2?
Options: 0.32 M, 0.032 M, or 0.0032 M
Answers: 1
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Which of these sequences lists the correct order for the creation of sedimentary rock from sediment? a. deposition, burial, compaction, cementation b. burial, deposition, compaction, cementation c. compaction, deposition, burial, cementation d. cementation, deposition, burial, compaction
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Fill in the coefficients that will balance the following reaction: a0cr2(so4)3 + a1agno3 -> a2cr(no3)3 + a3ag2so4
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The reaction below shows a system in equilibrium. how would a decrease in temperature affect this reaction? a. the rate of formation of the gases would increase. b. the equilibrium of the reaction would shift to the left. c. the equilibrium would shift to cause the gases to sublime into solids. d. the chemicals on the left would quickly form the chemical on the right.
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