HI(aq)+H2O(l)→ H3O+(aq)+I−(aq) Match the words to the appropriate blanks in the below sentences.

a. The Bronsted-Lowry ace is :
b. The Bronsted-Lowry base is :
c. The conjugate acid is :
d. The conjugate base is:

1. H2O(l)
2. HI(aq)
3. I^-
4. H2O^+

Given chemical reaction is:

HI(aq)+H2O(l)→ H3O+(aq)+I−(aq)

a. The Bronsted-Lowry ace is :

b. The Bronsted-Lowry base is :

c. The conjugate acid is :

d. The conjugate base is:

Explanation:

According to Bronsted-Lowry acid-base theory,

an acid is a substance, that is a proton donor.

A base is a proton acceptor.

The conjugate acid is formed from the base after gaining a proton.

The conjugate base is formed from the acid after losing a proton.

For the given reaction,

a. The Bronsted-Lowry acid is :__HI(aq)

b. The Bronsted-Lowry base is :_H2O(l)

c. The conjugate acid is :___H3O+(aq)

d. The conjugate base is:___I-(aq).

Explanation:

Bronsted -Lawry acid are hydrogen ion donators . Here HI  is Bronsted -Lawry acid.

HI   ⇄    H⁺   +   I⁻

Bronsted -Lawry base are those which can accept hydrogen ion .

I⁻  +  H⁺  ⇄   HI .

Conjugate acid -base pair are shown below .

          H₃O⁺        =        H⁺       +          H₂O .

conjugate acid                                    conjugate base .

( strong acid )                                       ( weak base )

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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