2 NaOH + H2SO4 2 H2O + Na2S04 a. How many grams of sodium sulfate will be formed if you start with 300 grams of sodium
hydroxide?

532.5 grams

Explanation:

The balanced chemical equation of this reaction is as follows:

2NaOH + H2SO4 → 2H2O + Na2S04

From the above balanced equation, it shows that 2 moles of sodium hydroxide (NaOH) produces 1 mole of sodium sulfate (Na2SO4).

Using mole = mass/molar mass to convert mass to mole

Molar mass of NaOH = 23 + 1 + 16 = 40g/mol

mole = 300/40

mole = 7.5moles of NaOH

Since 2 moles of sodium hydroxide (NaOH) produces 1 mole of sodium sulfate (Na2SO4).

Then, 7.5 moles of NaOH will produce 7.5/2 = 3.75moles of Na2SO4.

mole = mass/molar mass

Molar mass of Na2SO4 = 23(2) + 32 + 16(4)

= 46 + 32 + 64

= 142g/mol

Mass of Na2SO4 = 3.75 × 142

= 532.5g

the dependant variable is spilled water

the independent is the heat