Calculate the number of cations and anions in each of the following compounds. Enter your answers in scientific notation. (a) 6.42 g of KBr:

The number of cations are and number of anions are   in 6.42 g of KBr.

Explanation:

The molar mass of KBr is (39.10 + 79.90) g/mol = 119.00 g/mol

Now, the dissociation equation for KBr is as follows.

This means that 1 mole of KBr is forming 1 mole of (cation) and 1 mole of (anion).

According to mole concept, 1 mole of every substance contains atoms. Hence, number of cations present in 6.42 g KBr is calculated as follows.

As according to the equation, there are equal number of moles of both cation and anions.

This means that the number of anions are also .

Thus, we can conclude that the number of cations are and number of anions are   in 6.42 g of KBr.

the correct answer is answer a. a mixture

no other options make sense

hope this

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  - sprinkles

it is stable as it is in group 0 which have full outer shells of electrons