When Ethyl Acetoacetate is treated with 1,3-Dibromopropane and 2 moles of Sodium Ethoxide in Ethanol, a compound is produced that has the formula C9H14O3. This compound has an infrared spectrum that shows only one carbonyl adsorption and no OH bond stretch. Suggest a structure for this compound, and provide a mechanism for its formation.

The reaction of ethyl acetoacetate with 1,3-Dibromopropane and 2 moles of Sodium Ethoxide in Ethanol.

Explanation:

The structure of ethyl acetoacetate is shown below:

The structure of 1,3-dibromopropane is shown below:

Ethyl acetoacetate on reaction with sodium ethoxide in ethanol forms a carbanion intermediate and the formation of carbanion takes place twice and form a cyclic ring.

The entire reaction is shown below:

The structure of C9H14O3 is shown in the chemical reaction that is shown below:

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.