Arrange the following aqueous solutions in order from smallest to greatest freezing point depression: 0.400 m CaCl2, 0.400 m glucose or 0.400 m NaCl, Then determine the freezing point depression for each. For water, Kf = 1.86°C/m.

glucose<NaCl<CaCl2

Explanation:

Hello there!

In this case, since the general equation for the calculation of the freezing point depression is:

Whereas m and Kf are the same for the given salts, then we conclude that the greatest freezing point is exhibited by the salt with the greatest Van't Hoff's factor and the smallest freezing point with the smallest Van't Hoff's factor. In such a way, since this factor is equal to the number of ionized species, we infer that CaCl2 has i=3, glucose i=1 (nonionizing) and NaCl i=2; therefore, the order from smallest to greatest is:

glucose<NaCl<CaCl2

Regards!

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)