Presented by Machar Phosphorus pentachloride decomposes according to the chemical equation
PCI (9) PCI, (g) + Cl, (9) K = 1.80 at 250 °C
A 0.3723 mol sample of PCI; (g) is injected into an empty 4.25 L reaction vessel held at 250 °C.
Calculate the concentrations of PCI; (g) and PCI, (9) at equilibrium.
[PCI) =
M
[PC1,1 =
M

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given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g