If 50.0 mL of a 0.75 M hydrochloric acid solution is titrated with 1.0 M sodium hydroxide, what is the pH after 10.0 mL of NaOH have been added

Explanation:

moles of hydrochloric acid = 50 x 10⁻³ x .75 = 37.5 x 10⁻³ moles in HCl solutions.

moles of NaOH in its solution = 10 x 10⁻³ x 1 moles = 10 x 10⁻³ moles .

10 x 10⁻³ moles  of NaOH will neutralise 10 x 10⁻³ moles of HCl .

HCl remaining = (37.5 - 10 ) x 10⁻³ moles = 27.5 x 10⁻³ moles

volume of solution = 50 + 10 = 60 mL = 60 x 10⁻³ L

molarity of remaining HCl = 27.5 x 10⁻³ / 60 x 10⁻³

= .4583 M .HCl

concentration of H⁺ = .4583 M

pH = - log ( .4583 )

= .34 .

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a. energy is absorbed in the reaction.

if in a given reaction the energy of products is greater than the energy of reactants it means that reaction is endothermic and during the reaction, the energy is absorbed by reactants. in an endothermic reaction, the products have more stored chemical energy than the reactants. and in this reaction the reactants are more stable than products before the compounds with less energy are always more stable.